Applications of Derivatives · Theorems
Related Rates
Related rates problems involve finding how fast one quantity changes given how fast another changes. Differentiate an equation relating the quantities with respect to time.
- 2 worked examples
- 15 in Applications of Derivatives
Worked examples
- A = πr². Differentiate: dA/dt = 2πr · dr/dt
- dA/dt = 2π(5)(2) = 20π
Answer: dA/dt = 20π ≈ 62.83 cm²/s
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Common questions
What is the Related Rates?
Related rates problems involve finding how fast one quantity changes given how fast another changes. Differentiate an equation relating the quantities with respect to time. It is one of the applications of derivatives formulas in the CalcRef reference.
How do you use the Related Rates?
Worked example. A circle has radius growing at 2 cm/s. Find dA/dt when r = 5 cm. A = πr². Differentiate: dA/dt = 2πr · dr/dt. dA/dt = 2π(5)(2) = 20π. Answer: dA/dt = 20π ≈ 62.83 cm²/s.
Practice
Quiz yourself on Applications of Derivatives
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